(x^2/60)-26x+1550=0

Solution for (x^2/60)-26x+1550=0 equation:

(x^2/60)-26x+1550=0

We add all the numbers together, and all the variables

-26x+(x^2/60)+1550=0

We get rid of parentheses

x^2/60-26x+1550=0

We multiply all the terms by the denominator


x^2-26x*60+1550*60=0

We add all the numbers together, and all the variables

x^2-26x*60+93000=0

Wy multiply elements

x^2-1560x+93000=0

a = 1; b = -1560; c = +93000;
Δ = b2-4ac
Δ = -15602-4·1·93000
Δ = 2061600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2061600}=\sqrt{400*5154}=\sqrt{400}*\sqrt{5154}=20\sqrt{5154}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1560)-20\sqrt{5154}}{2*1}=\frac{1560-20\sqrt{5154}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1560)+20\sqrt{5154}}{2*1}=\frac{1560+20\sqrt{5154}}{2}
$